If the pressure of a gas contained in a closed vessel is increased by 0.4% when heated by `1^(@)C`, then its initial temperature must be:

Options

A. `-23^(@)C`
B. `+23^(@)C`
C. `250^(@)C`
D. `523^(@)C`

Explanation

`LetT_(1)=T Rightarrow T_(2)=(T+1)`
`p_(1)=p Rightarrow p_(2)=p+(0.4p)/(100)=(100.4)/(100)p`
`(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2)),(pV)/(T)=(100.4p)/(100)xx(V)/((T+1))`
`100T+100=100.4T`
`T=(100)/(0.4)=250K`
`(250-273)^(@)C=-23^(@)C`