For a chemical reaction `2X+YrarrZ`, the rate of appearance of Z is 0.05 mol `L^(-1)`. The rate of disappearance of X will be

Options

A. 0.05 mol `L^(-1) min^(-1)`
B. 0.05 mol `L^(-1) h^(-1)`
C. 0.1 mol `L^(-1) min^(-1)`
D. 0.25 mol `L^(-1) min^(-1)`

Answer

C

Explanation

`2X + Y rarr Z`
Hence, rate expression for the reaction will be
`-(1)/(2)(d[X])/(dt)=(d[Y])/(dt)=+(d[Z])/(dt)`
`therefore" "-(d[X])/(dt)=2xx0.05 " mol "L^(-1)" min"^(-1)`
`=0.1 " mol "L^(-1)" min"^(-1)`