For the reaction `2N_(2)O_(4)iff 4NO_(2)`, given that `(-d[N_(2)O_(4)])/(dt)=K " and "(d[NO_(2)])/(dt)=K`, then

Options

A. K=2K
B. K'=K
C. 2K'= K
D. None of these

Answer

A

Explanation

For this reaction,
`2N_(2)O_(4)iff 4NO_(2)`,
Rate expression `=-(1)/(2)(d[N_(2)O_(4)])/(dt)=(1)/(4)(d[NO_(2)])/(dt)`
`"or "-(d[N_(2)O_(4)])/(dt)=(1)/(2)(d[NO_(2)])/(dt)`
`"or "K=(1)/(2)K'`
`"or "K'=2K`