The rate for the decomposition of `NH_(3)` on platinum surface is zero order. What are the rate of production of `N_(2)` and `H_(2)` if `K = 2.5 xx 10^(-4) mol litre^(-1)s^(-1)`?

Options

A. `1.25 xx 10^(-4) " and mol "L^(-1)s^(-1) " and " 3.75 xx 10^(-4)" and mol "L^(-1) s^(-1)`
B. `3.75 xx 10^(-4) " and mol "L^(-1)s^(-1) " and " 1.25 xx 10^(-4)" and mol "L^(-1) s^(-1)`
C. `2.5 xx 10^(-4) " and mol "L^(-1)s^(-1) " and " 3.75 xx 10^(-4)" and mol "L^(-1) s^(-1)`
D. `1.25 xx 10^(-4) " and mol "L^(-1)s^(-1) " and " 2.5 xx 10^(-4)" and mol "L^(-1) s^(-1)`

Answer

A