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Consider the following reaction, 2N(2...

Consider the following reaction,
`2N_(2)O_(5)rarr4NO_(2)+O_(2),(d[NO_(2)] )/(dt)=k_(2)[N_(2)O_(5)]`,
`(d[O_(2)])/(dt)=k_(3)[N_(2)O_(5)]" and "(d)/(dt)[N_(2)O_(5)]=k_(1)`
The relation between `k_(1), k_(2)` and `k_(3)` is

A

`k_(1)=k_(2)=k_(3)`

B

`2k_(1)=k_(2)=4k_(3)`

C

`2k_(1)=4k_(2)=k_(3)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
`2N_(2)O_(5)rarr4NO_(2)+O_(2)`
Rate `=-(1)/(2)(d[N_(2)O_(5)])/(dt)=(1)/(4)(d[NO_(2)])/(dt)=(d[O_(2)])/(dt)` ltbgt `implies 2k_(1)=k_(2) =4k_(3)`
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2N_(2)O_(5) rarr 4NO_(2) + O_(2) If (-d[N_(2)O_(5)])/(dt) = k_(1)[N_(2)O_(5)] (d[NO_(2)])/(dt) = k_(2)[N_(2)O_(5)] (d[O_(2)])/(dt) = k_(3)[N_(2)O_(5)] What is the relation between k_(1), k_(2) , and k_(3) ?

For the reaction, N_(2)O_(5) rarr 2NO_(2)+1/2O_(2), Given -(d[N_(2)O_(5)])/(dt)=K_(1)[NO_(2)O_(5)] (d[NO_(2)])/(dt)=K_(2)[N_(2)O_(5)] and (d[O_(2)])/(dt)=K_(3)[N_(2)O_(5)] The relation in between K_(1), K_(2) and K_(3) is:

For the reaction, N_2O_5rarr2NO_2+1/2O_2 Given : -(d[N_2O_5])/(dt)=K_1[N_2O_5] (d[NO_2])/(dt)=K_2[N_2O_5] and (d[O_2])/(dt)=K_3[N_2O_5] The relation between K_1 , K_2 and K_3 is

The rate of reaction. 2N_(2)O_(5) to 4NO_(2) + O_(2) can be written in three ways. (-d[N_(2)O_(5)])/(dt) = k[N_(2)O_(5)] (d[N_(2)O_(5)])/(dt) =( k^(')[N_(2)O_(5)]) (d[O_(2)])/(dt) = (k^(')[N_(2)O_(5)]) The relation between k and k^(') are:

2N_2O_5 rarr 4 NO_2 +O_2 If -(D[N_2O_5])/(dt) =k_1[N_2O_5] (d[NO_2])/(dt) =k_2[N_2O_5] ([O_2])/(dt) =k_3[N_2O_5] What is the relation between k_1, k_2 and k_3 ? .

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