The rate constant of a reaction is `3.25 xx 10^(-3) " mol"^(-2) L^(2) " min"^(-1)`. The order of raction is

Options

A. zero
B. 1
C. 2
D. 3

Explanation

To determine the order of the reaction based on the given rate constant, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given rate constant**:
The rate constant \( k \) is given as \( 3.25 \times 10^{-3} \, \text{mol}^{-2} \, \text{L}^2 \, \text{min}^{-1} \).

2. **Understand the units of the rate constant**:
The units of the rate constant for a reaction of order \( n \) is given by:
\[ \text{Units of } k = \text{mol}^{1-n} \, \text{L}^{n-1} \, \text{min}^{-1} \]

3. **Set up the equation based on the units**:
From the given units of \( k \):
\[ \text{mol}^{-2} \, \text{L}^2 \, \text{min}^{-1} \]
We can equate the powers of mol and L to find \( n \).

4. **Analyze the power of mol**:
From the equation:
\[ 1 - n = -2 \]
Solving for \( n \):
\[ n = 1 + 2 = 3 \]

5. **Analyze the power of L**:
From the equation:
\[ n - 1 = 2 \]
Solving for \( n \):
\[ n = 2 + 1 = 3 \]

6. **Conclusion**:
Since both analyses give us \( n = 3 \), we conclude that the order of the reaction is 3.

### Final Answer:
The order of the reaction is **3**.

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