The half-life period of a first order process is 1.6 min. It will be 90% completed in

Options

A. 0.8 min
B. 3.2 min
C. 5.3 min
D. 1.6 min

Answer

C

Explanation

For first order reaction, `t_(1//2)=(0.693)/(k)`
`implies " "k=(0.693)/(1.6)=0.4332" min"^(-1)`
Now, for 90% completion,
`k=(2.303)/(t)log.(a)/(a-x)`
`implies " "0.4332=(2.303)/(t)log.(100)/(10)implies t=5.3min`