Let P be the point on parabola `y^2=4x` which is at the shortest distance from the center S of the circle `x^2+y^2-4x-16y+64=0` let Q be the point on the circle dividing the line segment SP internally. Then

Let P be the point on the parabola y^(2) = 4x which is at the shortest distance from the centre S of the circle x^(2) + y^(2) - 4x - 16y + 64 = 0 . Let Q be the point on the circle dividing the lie segment SP internally. Then

Find the point on y=x^2+4 which is at shortest distance from the line y=4x-4

The shortest distance from (-2,14) to the circle x^(2)+y^(2)-6x-4y-12=0 is

The shortest distance from the line 3x+4y=25 to the circle x^(2)+y^(2)=6x-8y is equal to :

Shortest distance between the centre of circle x^2+y^2-4x-16y+64=0 and parabola y^2=4x is:

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle,x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : (1) x^2+y^2-4x+8y+12=0 (2) x^2+y^2-x+4y-12=0 (3) x^2+y^2-x/4+2y-24=0 (4) x^2+y^2-4x+9y+18=0

Find the greatest distance of the point P(10,7) from the circle x^(2)+y^(2)-4x-2y-20=0

If the shortest distance of the parabola y^(2)=4x from the centre of the circle x^(2)+y^(2)-4x-16y+64=0 is "d" ,then d^(2) is equal to: