A circle S passes through the point (0, 1) and is orthogonal to the circles `(x -1)^2 + y^2 = 16` and `x^2 + y^2 = 1`. Then (A) radius of S is 8 (B) radius of S is 7 (C) center of S is (-7,1) (D) center of S is (-8,1)

If a circle Passes through point (1,2) and orthogonally cuts the circle x^(2)+y^(2)=4, Then the locus of the center is:

A circle passes through the points (0,0) and (0,1 ) and also touches the circie x^(2)+y^(2)=16 The radius of the circle is

If circle C passing through the point (2, 2) touches the circle x^2 + y^2 + 4x - 6y = 0 externally at the point (1, 1), then the radius of C is:

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is

The radius of the least circle passing through the point (8,4) and cutting the circle x^(2)+y^(2)=40 orthogonally is

If a circle C passing through the point (4,0) touches the circle x^(2)+y^(2)+4x-6y=12 externally at the point (1,-1) ,then the radius of C is

Find the equation(s) of circle passing through the points (1,1),(2,2) and whose radius is 1 unit

A circle S=0 passes through the common points of family of circles x^(2)+y^(2)+lambda x-4y+3=0 and (lambda varepsilon R) has minimum area then (A) area of S=0 is pi sq. units (C) radius of director circle of S=0 is 1 unit (D) S=0 never cuts |2x|=1 (B) radius of director circle of S=0 is sqrt(2)