The area enclosed by the curves`y= sinx+cosx and y = | cosx-sin x |` over the interval `[0,pi/2]`

The area enclosed by the curves y=sin x+cos x and y=|cos x-sin x| over the interval [0,(pi)/(2)]

The area enclosed by the curve y=sin x+cos x and y=|cos x-sin x| over the interval [0,(pi)/(2)] is 4(sqrt(2)-2) (b) 2sqrt(2)(sqrt(2)-1)2(sqrt(2)+1)(d)2sqrt(2)(sqrt(2)+1)

Using integration, find the area enclosed by the curve y = cos, y = sin x and x - axis in the interval [0, pi//2] .

Area enclosed by the curves y=sinx+cosx and y=abs(cosx-sinx) and the lines x=0 and x= pi/2

The angle between the curves y = sinx and y = cosx is

The area enclosed by the curve |y|=sin2x where x in[0,2 pi]. is

The area enclosed between the curve y=sin^(2)x and y=cos^(2)x in the interval 0le x le pi is _____ sq. units.