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Let Sn=sum(k=1)^(4n)(-1)(k(k+1))/2k^2dot...

Let `S_n=sum_(k=1)^(4n)(-1)(k(k+1))/2k^2dot` Then `S_n` can take value (s) `1056` b. `1088` c. `1120` d. `1332`

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