Let `z_k = cos(2kpi/10)+isin(2kpi/10); k=1,2,34,...,9` (A) For each `z_k` there exists a `z_j` such that `z_k.z_j=1` (ii) there exists a `k in {1,2,3,...,9}` such that `z_1 z = z_k`

Let quad cos(2k(pi)/(10))+i sin(2k(pi)/(10));k=1,2,34,...,9z_(k)=cos(2k(pi)/(10))+i sin(2k(pi)/(10));k=1,2,34,...,9 (A) For each z_(k) there exists a z_(j) such that z_(k).z_(j)=1 (ii) there exists a k in{1,2,3,...,9} such that z_(1)z=z_(k)

Let z_(k)=cos(2kpi)/10+isin(2kpi)/10,k=1,2,………..,9 . Then, 1/10{|1-z_(1)||1-z_(2)|……|1-z_(9)|} equals

If z_(k)=cos((k pi)/(10))+i sin((k pi)/(10)), then z_(1)z_(2)z_(3)z_(4) is equal to (A)-1 (B) 2(C)-2 (D) 1

Let z_(k) = cos ((2kpi)/(7))+i sin((2kpi)/(7)),"for k" = 1, 2, ..., 6 , then log_(7)|1-z_(1)|+log_(7)|1-z_(2)|+....+ log_(7)|1-z_(6)| is equal to ________

The equation of the locus of z such that |(z-i)/(z+i)|=2 , where z=x+iy is a complex number,is 3x^(2)+3y^(2)+10y+k=0 then k=

Prove that |z-z_1|^2+|z-z_2|^2 = k will represent a circle if |z_1-z_2|^2 le 2k.

If z_(1),z_(2),z_(3),…………..,z_(n) are n nth roots of unity, then for k=1,2,,………,n

The locus of the point z satisfying arg [( z - 1)/(z+1)] = k,where k is non zero is :