The circle `x^ 2 + y^ 2 − 8 x = 0` and hyperbola `x^ 2/ 9 − y^ 2/ 4 = 1` intersect at points A and B. Then Equation of the circle with A B as its diameter is

The circle x^(2)+y^(2)-8x=0 and hyperbola (x^(2))/(9)-(y^(2))/(4)=1 intersect at the points A and B Equation of the circle with AB as its diameter is

The line x=2y intersects the ellipse (x^(2))/4+y^(2)=1 at the points P and Q . The equation of the circle with PQ as diameter is

The circle x^(2)+y^(2)-8x=0 and hyperbola (x^(2))/(9)-(y^(2))/(4)=1 intersect at the points A and B . The equation of a common tangent with positive slope to the circle as well as to the hyperbola, is

The circle x^(2)+y^(2)-8x=0 and hyperbola (x^(2))/(9)-(y^(2))/(4)=1 I intersect at the points A and B.Equation of a common tangent with positive slope to the circle as well as to the hyperbola is

Let the line segment joining the centres of the circles x^(2)-2x+y^(2)=0 and x^(2)+y^(2)+4x+8y+16=0 intersect the circles at P and Q respectively. Then the equation of the circle with PQ as its diameter is

If x-y+1=0 meets thwe cicle x^(2)+y^(2)+y-1=0 at a and b, then the equation of the circle with ab as diameter, is

The circles x^2 + y^2 - 4x - 81 =0 and x^2 + y^2 + 24x - 81=0 intersect each other at A and B . The equation of the circle with AB as the diameter is : (A) x^2 + y^2 = 81 (B) x^2 + y^2 = 9 (C) x^2 + y^2 = 16 (D) x^2 + y^2 = 1

If line y= 2x meets circle x^(2) + y^(2) - 4x = 0 in point A and B , then equation of circle of which AB is diameter is

The circle x^(2)+y^(2)=4 cuts the circle x^(2)+y^(2)+2x+3y-5=0 in A and B ,Then the equation of the circle on AB as diameter is