Prove that the function given by `f(x)=x^3-3x^2+3x-100`is increasing in R.

Explanation

To prove that the function \( f(x) = x^3 - 3x^2 + 3x - 100 \) is increasing in \( \mathbb{R} \), we will follow these steps:

### Step 1: Find the derivative of the function
The first step is to find the derivative of the function \( f(x) \).

\[ f'(x) = \frac{d}{dx}(x^3 - 3x^2 + 3x - 100) \]
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