Consider the system of equations `x-2y+3z=-1, x-3y+4z=1` and `-x+y-2z=k` Statement 1: The system of equation has no solution for `k!=3` and Statement 2: The determinant `|[1,3,-1], [-1,-2,k] , [1,4,1]| !=0` for `k!=0`

Consider the system of equations x-2y+3z=-1 -x+y-2z=k x-3y+4z=1 Statement -1 The system of equation has no solutions for k ne 3 . statement -2 The determinant |{:(1,3,-1),(-1,-2,k),(1,4,1):}| ne0, "for"" " kne3.

Consider the system of equations x-2y+3z=1;-x+y-2z=; x-3y+4z=1. Statement 1: The system of equations has no solution for k!=3. Statement2: The determinant |1 3-1-1-2k1 4 1|!=0,\ for\ k!=3. Statement 1 is True: Statement 2 is True; Statement 2 is a correct explanation for statement 1 Statement 1 is true, Statement 2 is true;2 Statement 2 not a correct explanation for statement 1. Statement 1 is true, statement 2 is false Statement 1 is false, statement 2 is true

Consider the system of equations x-2y+3z=-1, -x+y-2z=k, x-3y+4z=1 Assertion: The system of equations has no solution for k!=3 and Reason: The determinant |(1,3,-1),(-1,-2,k),(1,4,1)|!=0, for k!=3 (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

Consider the system of the equation k x+y+z=1,x+k y+z=k ,a n dx+y+k z=k^2dot Statement 1: System equations has infinite solutions when k=1. Statement 2: If the determinant |1 1 1k k1k^2 1k|=0, t hen k=-1.

kx+y+z=1 , x+ky+z=k , x+y+kz=k^2 be the system of equations with no solution , then k=

Solve the system of equations x+2y+3z=1,2x+3y+2z=2 and 3x+3y+4z=1 with the help of matrix inversion.

If the system of equations 3x+y+z=1, 6x+3y+2z=1 and mux+lambday+3z=1 is inconsistent, then

The solution of the system of equations is x-y+2z=1,2y-3z=1 and 3x-2y+4y=2 is

The system of linear equations x - 2y + z = 4 2x + 3y - 4z = 1 x - 9y + (2a + 3)z = 5a + 1 has infinitely many solution for: