Tangents drawn from the point `P(1, 8)` to the circle `x^2+ y^2-6x-4y-11=0` touch the circle at the points `A` and `B`. The equation of the circumcircle of the triangle `PAB` is
(A) `x^2 +y^2 + 4x-6y + 19=0`
(B) `x^2 +y^2-4x-10y + 19=0`
(C) `x^2 + y^2-2x + 6y-29 = 0`
(D) `x^2 + y^2-6x-4y + 19 = 0`

The nearest point on the circle x^(2)+y^(2)-6x+4y-12=0 from (-5,4) is

The inverse of the point (1,2) with respect to circle x^(2)+y^(2)-4x-6y+9=0

Tangents are drawn from a point on the circle x^(2)+y^(2)-4x+6y-37=0 to the circle x^(2)+y^(2)-4x+6y-12=0 . The angle between the tangents, is

Tangents drawn from P(1,8) to the circle x^(2)+y^(2)-6x-4y-11=0 touches the circle at the points A and B, respectively.The radius of the circle which passes through the points of intersection of circles x^(2)+y^(2)-2x-6y+6=0 and x^(2)+y^(2)-2x-6y+6=0 the circumcircle of the and interse Delta PAB orthogonally is equal to

y-1=m_1(x-3) and y - 3 = m_2(x - 1) are two family of straight lines, at right angled to each other. The locus of their point of intersection is: (A) x^2 + y^2 - 2x - 6y + 10 = 0 (B) x^2 + y^2 - 4x - 4y +6 = 0 (C) x^2 + y^2 - 2x - 6y + 6 = 0 (D) x^2 + y^2 - 4x - by - 6 = 0

The length of the tangent from a point on the circle x^(2)+y^(2)+4x6y-12=0 to the circle x^(2)+y^(2)+4x6y+4=0 is

Find the point of contact of the tangent x+y-7=0 to the circle x^2+y^2-4x-6y+11=0

The equation of the circle which inscribes a suqre whose two diagonally opposite vertices are (4, 2) and (2, 6) respectively is : (A) x^2 + y^2 + 4x - 6y + 10 = 0 (B) x^2 + y^2 - 6x - 8y + 20 = 0 (C) x^2 + y^2 - 6x + 8y + 25 = 0 (D) x^2 + y^2 + 6x + 8y + 15 = 0

Three sides of a triangle are represented by lines whose combined equation is (2x+y-4) (xy-4x-2y+8) = 0 , then the equation of its circumcircle will be : (A) x^2 + y^2 - 2x - 4y = 0 (B) x^2 + y^2 + 2x + 4y = 0 (C) x^2 + y^2 - 2x + 4y = 0 (D) x^2 + y^2 + 2x - 4y = 0