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The axis of a parabola is along the line...

The axis of a parabola is along the line `y=x` and the distance of its vertex and focus from the origin are `sqrt(2)` and `2sqrt(2)` , respectively. If vertex and focus both lie in the first quadrant, then the equation of the parabola is `(x+y)^2=(x-y-2)` `(x-y)^2=(x+y-2)` `(x-y)^2=4(x+y-2)` `(x-y)^2=8(x+y-2)`

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The axis of parabola is along the line y=x and the distance of its vertex and focus from origin are sqrt(2) and 2sqrt(2) respectively.If vertex and focus both lie in the first quadrant,then the equation of the parabola is:

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A parabola has its vertex and focus in the first quadrant and axis along the line y=x . If the distances of the vertex and focus from the origin are respectively sqrt(2)&2sqrt(2) , then equation of the parabola is x^2+y^2-8x+8y+2x y=16 x^2+y^2-8x-8y+16=2x y (x-y)^2=8(x+y-2) (x+y)^2=(x-y+2)