Total number of moles of `P-H` bond(s) in product(s) when one mole of white `P_(4)` completely reacts with KOH solution:

Explanation

To determine the total number of moles of P-H bonds produced when one mole of white phosphorus (P₄) reacts completely with KOH solution, we can follow these steps:

### Step 1: Write the Reaction Equation
When white phosphorus (P₄) reacts with KOH, it produces phosphine (PH₃) and potassium hypophosphite (KH₂PO₂). The balanced reaction is:

\[ P_4 + 4 KOH + 2 H_2O \rightarrow 2 PH_3 + 2 KH_2PO_2 \]

### Step 2: Identify the Products
From the balanced equation, we can see that the products formed are:
- 2 moles of PH₃
- 2 moles of KH₂PO₂

### Step 3: Count the P-H Bonds in Each Product
1. **For PH₃**:
- Each molecule of PH₃ contains 3 P-H bonds.
- Therefore, for 2 moles of PH₃:
\[ 2 \text{ moles of PH}_3 \times 3 \text{ P-H bonds/mole} = 6 \text{ P-H bonds} \]

2. **For KH₂PO₂**:
- Each molecule of KH₂PO₂ contains 2 P-H bonds.
- Therefore, for 2 moles of KH₂PO₂:
\[ 2 \text{ moles of KH}_2PO_2 \times 2 \text{ P-H bonds/mole} = 4 \text{ P-H bonds} \]

### Step 4: Calculate the Total Number of P-H Bonds
Now, we can add the number of P-H bonds from both products:
\[ 6 \text{ P-H bonds (from PH}_3) + 4 \text{ P-H bonds (from KH}_2PO_2) = 10 \text{ P-H bonds} \]

### Step 5: Determine the Total Moles of P-H Bonds
Since we are asked for the total number of moles of P-H bonds, we can express the total number of P-H bonds as moles:
\[ \text{Total moles of P-H bonds} = 10 \text{ moles} \]

Thus, the total number of moles of P-H bonds produced when one mole of white phosphorus reacts completely with KOH solution is **10 moles**.

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