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A ring of diameter 0.4 m and of mass 10 ...

A ring of diameter 0.4 m and of mass 10 kg is rotating about its geometrical axis at the rate of 35 ratation/second. Find the moment of intertia.

A

`0.1`

B

`0.2`

C

`0.3`

D

`0.4`

Text Solution

Verified by Experts

The correct Answer is:
D

Moment of intertia of the ring about its axis is
`I=MR^(2)`
`I=10xx(0.2)^(2)=10xx0.04 =0.4 "kg-m"^(2)`.
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