The moment of inertia of a solid cylindrer about its axis of ratation is `(MR^(2))/(2)`. What is the value if the radius of gyration of the cylinder about this axis ?

Explanation

Moment of inertia of solid cylinder, `I=(MR^(2))/(2)`....(i)
Moment of inertia, `I=MK^(2)`….(ii)
Comparing Eqs. (i) and (ii), we have
`K^(2)=(R^(2))/(2).K=(R)/(sqrt(2))`m