Find the moment of inertia of a sphere about a tangent to the sphere, while the mass of the sphere is M and the radius of the sphere is R.

Explanation

The moment of inertia of a sphere about its
own axis (YY') is `(2MR^(2))/(5)`
Applying the throrem of parallel axes the moment of inertia of the sphere about tangent `(XX')`
`I_(t) = I+MR^(2)`
`I_(t)=(2)/(5)MR^(2)+MR^(2)=(7)/(5)MR^(2)`