Consider a uniform rod of mass m and length 2l with two particles of mass `m` each at its ends. Let AB be a line perpendicular to the length of rod and passig through its centre. Find the moment of inertial of the system about AB.

Explanation

Moment of inertia of the system about AB
`I_(AB)=I_("rod")+I_("both particles")`
`=(m(2l)^(2))/(12)+2(ml^(2))=(7)/(3)ml^(2)`.