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the center of a wheel rolling on a plane...

the center of a wheel rolling on a plane surface moves with a speed `v_(0)`. A particle on the rim of the wheel at the same level as the center will be moving at speed

A

zero

B

`v_(0)`

C

`sqrt(2)v_(0)`

D

`2v_(0)`

Text Solution

Verified by Experts

The correct Answer is:
C
Speed of particle, `v_(P)=r omega = (sqrt(2)R)omega = sqrt(2)v_(0)`
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