The radius of gyration of a uniform rod of length `L` about an axis passing through its centre of mass is

Options

A. `(L)/(2 sqrt(3))`
B. `(L^(2))/(12)`
C. `(L)/(sqrt(3))`
D. `(L)/(sqrt(2))`

Answer

A

Explanation

Since, for uniform rod, the moment of inertia about an axis passing through its centre is `ML^(2)//12`
`K=sqrt((I)/(m))=sqrt(((mL^(2)//12))/(m))=(L)/(2sqrt(3))`.