Five particles of mass 2 kg are attached to the rim of a circular disc of radius 0.1 m & negligible mass. Moment of inertia of the system about an axis passing through the centre of the disc & perpendicular to its plane is

Options

A. `1 "kg-m"^(2)`
B. `0.1 "kg-m"^(2)`
C. `2 "kg-m"^(2)`
D. `0.2 "kg-m"^(2)`

Answer

B

Explanation

Moment of inertia of the system
`I=5mR^(2)=5xx2xx(0.1)^(2)=0.1 "kg-m"^(2)`