If the equation for the displacement of a particle moving on a circle path is given by, `theta = 2t^(2)+0.5` where, `theta` is in radian and `t` is in second, then the angular velocity of the particle after 2 s is

Options

A. `8 rad s^(-1)`
B. `12 rad s^(-1)`
C. `24 rad s^(-1)`
D. `36 rad s^(-1)`

Answer

C

Explanation

Angular velocity, `omega=(d theta)/(dt)=6t^(2)`, At `t=2s`
`omega = 6(2)^(2)=24 "rads"^(-1)`.