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A particle of mass m is projected with v...

A particle of mass m is projected with velocity v moving at an angle of `45^(@)` with horizontal. The magnitude of angular momentum of projectile about point of projection when particle is at maximum height, is

A

zero

B

`(mvh)/(sqrt(2))`

C

`mvh`

D

`sqrt(2) mvh`

Text Solution

Verified by Experts

The correct Answer is:
B
The magnitude of angular momentum,
`L = mvr_(bot)`
`rArr L=(mvh)/(sqrt(2))`
.
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