A sphere of mass `M` rolls without slipping on rough surface with centre of mass has constant speed `v_0`. If mass of the sphere is `m` and its radius be R`, then the angular momentum of the sphere about the point of contact is.

Options

A. `(5)/(7) Mv_(0)R`
B. `(7)/(5)Mv_(0)R`
C. `(3)/(5)Mv_(0)R`
D. `(1)/(2)Mv_(0)R`

Answer

B

Explanation

About bottomost point,

The angularm momentum of sphere,
`L=MRv_(0)+(2)/(5)MR^(2)((v_(0))/(R))=(7)/(5)MRv_(0)`.