Two uniform, thin identical rods each of mass M and length `l` are joined together to form a cross. What will be the moment of inertia of the cross about an axis passing through the point at which the two rods are joined and perpendicular to the plane of the cross ?

Options

A. `(Ml^(2))/(12)`
B. `(Ml^(2))/(6)`
C. `(Ml^(2))/(4)`
D. `(ML^(2))/(3)`

Answer

B

Explanation

Moment of inertia, `I=4 [(M)/(2)((l//2)^(2))/(3)]=(Ml^(2))/(6)`