A solid sphere and a solid cylinder of same mass are rolled down on two inclined planes of heights `h_(1) and h_(2)` respectively. If at the bottom of the plane the two objects have same velocities, then the ratio of `h_(1) : h_(2)` is

Options

A. `2:3`
B. `7:5`
C. `14:15`
D. `15:14`

Answer

C

Explanation

According to the question,
`(K_(T))_("sphere")=(K_(T))_("Cylinder")" "("m and v are same")`
`:. (5)/(7)(mgh_(1))=(2)/(3)(mgh_(2))rArr(h_(1))/(h_(2))=(14)/(15)`.