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100g ice at 0^(@)C is mixed with 100g wa...

`100g` ice at `0^(@)C` is mixed with `100g` water at `100^(@)C`. The resultant temperature of the mixture is

A

`10^(@)C`

B

`20^(@)C`

C

`30^(@)C`

D

`0^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
Heat lost = Heat gained
`therefore` (100 xx 80) + (100 xx1 xx T) = 100 xx 1xx(100 -T)`
or T`=10^(@)`C
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