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A liquid of mass m and specific heat c i...

A liquid of mass m and specific heat c is heated to a temperature 2T. Another liquid of mass m/2 and specific heat 2 c is heated to a temperature T. If these two liquids are mixed, the resulting temperature of the mixture is

A

` (2//3) T`

B

`(8//5)T`

C

`(3//5)T`

D

`(3//2)T`

Text Solution

Verified by Experts

The correct Answer is:
D
Temperature of mixture,
`theta(mix) = ((m_(1)c_(1)T_(1)+ m_(2)c_(2)T_(2))/(m_(1)c_(1)+ m_(2)c_(2))` = `(m xx cxx 2T+(m/2)(2c)T)/(mxxc+m/2(2c)) = 3/2 T`
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