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A factory worker pushes a 25.0 kg crate ...

A factory worker pushes a 25.0 kg crate downward at an angle of `30^(@)` below the horizontal a distance of 6.0 m along a level floor.
(a) What magnitude of force must the worker apply to move the crate at constant velocity, if the coefficient of kinetic friction between the crate and floor is 0.3 ?
(b) How much work is done on the crate by this force when the crate is pushed a distance of 6.0 m?
(c) How much work is done on the crate by friction during this displacement ?
(d) How much work is done by the normal force and by gracity ?
(e) What is the total work done on the crate ? Take `g=10m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
[(a) 104.74 N; (b) 544.27 J; (c) -544.27 J, (d) 0,0;(e)0]
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Knowledge Check

  • A horizontal force F pulls a 20 kg box at a constant speed along a horizontal floor. If the coefficient of friction between the box and the floor is 0.25,how much work is done by the force F in moving the box through a distance of 2 m?

    A
    49J
    B
    98J
    C
    147J
    D
    196J
  • If the coefficient of kinetic friction be in above question then the initial acceleration of the crate will be :

    A
    `[((T)/(mg))(costheta+mu_(k)sintheta)+mu_(k)]g`
    B
    `[((T)/(mg))(costheta+mu_(k)sintheta)-mu_(k)]g`
    C
    `[((T)/(mg))(sintheta+mu_(k)sintheta)-mu_(k)]g`
    D
    `[((T)/(mg))(sintheta+mu_(k)sintheta)+mu_(k)]g`
  • A forward horizontal force of 12 N is used to pull a 240 N crate at constant velocity across a horizontal floor. The coefficient of friction is

    A
    0.5
    B
    0.05
    C
    2
    D
    0.2
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