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A small coin of mass 80g is placed on th...

A small coin of mass `80g` is placed on the horizontal surface of a rotating disc. The disc starts from rest and is given a constant angular acceleration `alpha=2rad//s^(2)`. The coefficient of static friction between the coin and the disc is `mu_(s)=3//4` and cofficient of kinetic friction is `mu_(k)=0.5`. The coin is placed at a distance `r=1m` from the centre of the disc. The magnitude of the resultant force on the coin exerted by the disc just before it starts slipping on the disc is

A

`({((u_(s)g)^(2)/(r))+alpha^(2)}^(1//2))/(4pialpha)`

B

`({((u_(s)g)^(2)/(r))-alpha^(2)}^(1//2))/(4pialpha)`

C

`({((u_(s)g)^(2)/(r))-alpha^(2)}^(1//2))/(2pialpha)`

D

`({((u_(s)g)^(2)/(r))+alpha^(2)}^(1//2))/(2pialpha)`

Text Solution

Verified by Experts

The correct Answer is:
B
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