A aprtical moves on a rough horizontal g...

A aprtical moves on a rough horizontal ground with same initial velocity say `v_(0)`. If `(3//4)th` of its kinetic energy is lost in friction in time `t_(0)` , then coefficient of friction between the partical and the ground is:

`v_(0)/(2gt^(0))`

`v_(0)/(4gt_(0))`

`(3v_(0))/(4gt_(0))`

`v_(0)/(gt_(0))`

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