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A 1.5-kg block is initially at rest on a...

A `1.5-kg` block is initially at rest on a horizontal frictionless surface when a horizontal force in the positive direction of x-axis is applied to the block. The force is given by `vecF=(4-x^2)veciN`, where x is in meter and the initial position of the block is `x=0`.
The maximum positive displacement x is

A

2.33 J

B

8.67 J

C

5.33 J

D

6.67 J

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The correct Answer is:
C
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