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If the distance between the two point ch...

If the distance between the two point charges is doubled then what will be percentage change in the force?

Text Solution

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Since `F prop 1/(d^(2)),F^(1)=(Fd^(2))/((d^(1))^(2))`
i.e. `F^(1)=F(d/(2d))^(2)`
i.e `F^(1)=F/4`
Percentage decrease in the fore `=(F-F//4)/Fxx100=75%`
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