One mole of an ideal gas is allowed to expand reversible and adiabatically from a temperatureof`27^(@)C)`if the work done during the process is`3`kJ,the final temperature will be equal to`(C_(v)=20JK^(-1))`

Options

A. 100K
B. 150K
C. 295K
D. `26.85^(@)C`

Answer

B

Explanation

`C_(v) = (q)/(Delta T)` For adiabatic Process q=0, `Delta U = W, Delta U = W=nC_(v)Delta T`
`-3000 J = 1 xx 20J.Delta T`
`T_(2) = 150 K`