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Lattice energy of NaCl((s)) is -788kJ mo...

Lattice energy of `NaCl_((s))` is `-788kJ mol^(-1)` and enthalpy of hydration is `-784kJ mol^(-1)`. Calculate the heat of solution of `NaCl_((s))`.

A

`-4kJ`

B

`4KJ`

C

`-6KJ`

D

`2KJ`

Text Solution

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The correct Answer is:
B
heat of solution = L.E+H.E
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