One mole of an ideal gas (`C_(V) = 20 JK^(-1) mol^(-1))` initially at STP is heated at constant volume to twice the initial temeprature. For the process W and q will be

Options

A. W = 0, q = 5.46 kJ
B. W = 0,q=0
C. W = -5.46kJ, q = 5.46 kJ
D. W=5.46kJ, q = 5.46 kJ

Answer

A

Explanation

`W = P Delta V = P xx 0 = 0`
`Q = C_(V) (Delta T) = 20 xx 273 = 5460 J = 5.46 kJ`