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If enthaopy of hydrogenation of C(6)H(6)...

If enthaopy of hydrogenation of `C_(6)H_(6)(l)` into `C_(6)H_(12)(l)` is `-205kJ//mol` and resonance energy of `C_(6)H_(6)(l)` is `-152kJ//mol` then enthaopy of hydrogenation of

Assume `DeltaH_("vap")` of `C_(6)H_(6)(l),C_(6)H_(8)(l)` all equal :

A

`-535.5 kJ//mol`

B

`-238 kJ//mol`

C

`-357 kJ//mol`

D

`-119kJ//mol`

Text Solution

Verified by Experts

The correct Answer is:
D

`= -205 - 152 = -357`
Enthalpy of hydrogenation of , `(-337)/(3) = -119kJ//mol`
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