Calculate `DeltaS` for 3 mole of a diatomic ideal gas which is heated and compressed from 298 K and 1 bar to 596 K and 4 bar: [Given: `C_(v,m)(gas)=(5)/(2)R,"ln"(2)=0.70,R=2"cal K^(-1)mol^(-1)`]

Options

A. `-14.7 cal K^(-1)`
B. `+14.7 cal K^(-1)`
C. `-4.9 cal K^(-1)`
D. `6.3 cal K^(-1)`

Answer

D

Explanation

`Delta S = nC_(p m)ln.(T_(2))/(T_(1)) + nR ln.(P_(1))/(P_(2))`
`= 3 xx (7)/(2)R ln ((596)/(298)) + 3Rln.(1)/(4) = 6.3 cal K^(-1)`