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Heat of neutralisation of strong acid an...

Heat of neutralisation of strong acid and strong base under `1 atm` and `25^@C` is `-13.7 kcal`. If standard Gibbs energy change for dissociation of water to `H^+` and `OH^-` is `-19.14 kcal`, the change in standard entropy for dissociation of water is:

A

`18.25`

B

`110.2`

C

`-18.25`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A

for `H_(2)O hArr T Delta S^(@) Delta H^(@)`
`Delta S^(@) = (Delta H^(@)-Delta G^(@))/(T)`
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