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Molar enthalpy of vaporization of a liqu...

Molar enthalpy of vaporization of a liquid is 2.6 kJ. If boiling point of this liquid is `160^(@)c`, the molar entropy of vaporization (in `JK^(-1)`) unit is

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The correct Answer is:
6
`Delta S=(Delta H)/(T) =(2.6xx10^(3))/(433)=6`
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