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An AC voltage e=e(0)sin50t-e(0)cos100pit...

An AC voltage `e=e_(0)sin50t-e_(0)cos100pit` is connected in series with a resistor and capacitor. The steady state current through circuit is found to be `I=I_(0)sing(50pit+phi)+I_(0)'cos(100pit+phi_(2))`
Then, the ratio of `(I_(0))/(I_(0)'` is

A

greater than 1

B

equal to 1

C

less than 1

D

None of these

Text Solution

Verified by Experts

( C ) `l_(0)=(E_(0))/(sqrt(R^(2)+X_(C)=^(2)))=(E_(0))/(sqrt(R^(2)+(1/(50 C ))^(2)))`
Similarly ,
`l'_(0)=(E_(0))/sqrt(R^(2)+(1/(100 C))^(2))` Hence ,l_(0)ltl_(0)`
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