Home
Class 12
PHYSICS
If a circuit made up of a resistance 1 O...

If a circuit made up of a resistance 1 `Omega` and inductance 0.01 H, an alternating emf of 200 voit at 50 Hz is connected, then find the phase difference between the current and the emf in the circuit.

A

`tan^(-1)(pi)`

B

`tan^(-1)((pi)/(2))`

C

`tan^(-1)((pi)/(4))`

D

`tan^(-1)((pi)/(3))`

Text Solution

Verified by Experts

(a)`"tan"phi=((X_(L))/(R))` and `X_(L)=OmegaL=(2pifL)=(2pi)(50)(0.01)=piomega`
also `R=1Omegaimplies phi="tan"^(-1)(pi)`
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT AND EM WAVE

    BITSAT GUIDE|Exercise BITSAT Archives|15 Videos

  • ATOMIC STRUCTURE

    BITSAT GUIDE|Exercise BITSAT Archives|4 Videos

Similar Questions

Explore conceptually related problems

In resonant circuits, at resonance, the phase difference between current and emf is

A pure inductance is connected to an AC source. What will be the phase difference between the current and the EMF in the circuit?

A coil of resistance 500 Omega and inductance 1.4 H is connected to an alternating voltage supply of frequency 100 //pi Hz. What is the phase difference between the voltage and current in the circuit ?

An alternating emf 200 virtual volts at 50 Hz is connected to a circuit resistance 1omega and inductance 0.01 H . What is the phase difference between the current and the emf in the circuit? Also, find the virtual current in the circuit.

A circuit consists of a resistance 10 ohm and a capacitance of 0.1 mu F If an alternating e.m.f. of 100 V. 50 Hz is applied, calculate the current in the circuit.

A coil of resistance 300 Omega and inductance 1.0 henry is connected across an voltages source of frequency 300//2pi Hz . The phase difference between the voltage and current in the circuit is

An AC circuit contains a resistance of 40 Omega and an inductance of 0.68 H and an alternating effective emf of 500 V at a frequency of 125 cycles/s. Then, the current in the circuit is

An a.c. circuit contains a resistance of 3 Omega and inductive reactance of 4Omega . The cosine of the phase angle between the current and potential difference in this circuit is

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be