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Voltage V and current I in AC circuit ar...

Voltage V and current I in AC circuit are given by V =50sin(50 t)volt,I = 50 sin (`50t+(pi)/(3)`)mA
The power dissipated in the ciruit is

A

5.0 W

B

2.5 W

C

1.25 W

D

zero

Text Solution

Verified by Experts

(c) Given , `V=50"sin"(50t) V`
Maximum voltage , `V_(0)=50V , I =50"sin"(50t+(pi)/(3))mA`
Maximum current , `i_(0)=50 mA =50 xx 10^(-3)A`
power dissipated , `P=(i_(0))/(sqrt(2))xx(V_(0))/(sqrt(2))`
`=(50xx50xx10^(-3))/(2)`
`=(2500xx10^(-3))/(2)=1.25 W`
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