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A charged particle of mass `m` and charge `q` is accelerated through a potential differences of `V` volts. It enters of uniform magnetic field `B` which is directed perpendicular to the direction of motion of the particle. The particle will move on a circular path of radius

A

`sqrt((Vm)/(qB^(2)))`

B

`(2Vm)/(qB^(2))`

C

`sqrt((2Vm)/q)(1/B)`

D

`sqrt((Vm)/q)(1/B)`

Text Solution

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The correct Answer is:
c
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