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Let binding energy per nucleon of nucleu...

Let binding energy per nucleon of nucleus is denoted by `underset(bn)(E)` and radius is denoted as r. If mass number of nuclei A,B are 64 and 125 respectively , then

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The correct Answer is:
D
r = `r_(0)(A)^(1/3)`
r increases with increasing A mass number.
So, `r_(A)`lt`r_(B)` as mass number of A is smaller `E_(bn)` decreases with increasing A for `A gt 56^(56)`Fe has highest `E_(bn)` value.
So, `E_(bn)` for A = 64 is larger as compared to `E_(bn)` for nucleus with A = 125
`E_(bnAgtE_(bnB)`
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The binding energy per nucleon of a heavier nucleus is 6.8 MeV and binding energy per nucleon for the intermediate mass is 8.0 MeV during a nuclear fission. If the total number of nucleons is 270, what is the energy released during one fission?

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Knowledge Check

  • Let binding energy per nucleon of nucleus is denoted by E_(bn) and radius of nucleus is denoted as r. If mass number of nuclei A, B and 64 and 125 respectively then

    A
    `r_A lt r_B, E_(bnA) lt E_(bnB)`
    B
    `r_A gt r_B. E_(bnA) gt E_(bnB)`
    C
    `r_A = 4/5 r_B , E_(bnA) lt E_(bnB)`
    D
    `r_A lt r_B. E_(bnA) gt E_(bnB)`

  • Binding energy per nucleon relation with mass number

    A
    first decreases then increases
    B
    first increases then decreases
    C
    increases
    D
    decreases

  • The value of binding energy per nucleon is maximum for the elements having the mass number

    A
    more than 10
    B
    between 50 to 100
    C
    more than 100
    D
    between 100 to 200

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