The magnetic moment of the current carrying loop shown in the figure is equal to

Options

A. `(l(b^(2)+2ab)theta)/2`
B. `lab theta`
C. `(l(a^(2)+ba)theta)/2`
D. None of the above

Answer

a

Explanation

Magnetic moment
`M=lA=l(A_(2)-A_(1))`
`=l{((a+b)^(2))/2 theta-(a^(2))/2 theta} =(l(b^(2)+2ab) theta)/2`